fix(arg-parser): a quoted value stops at a quote that starts a word and never swallows a later flag
Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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2 changed files with 32 additions and 6 deletions
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@ -135,10 +135,17 @@ const isSpace = (c) => /\s/.test(c);
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/**
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* Split argument text into words. Words are separated by whitespace. A word
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* that starts with `'` or `"` and has the same quote again at the end of a
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* later word is a balanced pair: the pair groups the words between them into
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* one value and is removed. A quote with no such partner is a literal
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* character (`user's` stays `user's`). Nothing is expanded.
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* that starts with `'` or `"` opens a quote. Its closing quote is the next
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* same-kind quote that ends a word (followed by whitespace or the end of the
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* text) and does not start one; a same-kind quote inside a word is skipped.
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* The search stops at a same-kind quote that starts a word (one preceded by
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* whitespace): then there is no pair. A pair groups the words between the
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* quotes into one value and is removed. A quote with no partner is a literal
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* character (`user's` stays `user's`). Examples: `'Fix the user's login'` is
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* one value, `Fix the user's login`; `"my dir"/x --since "HEAD~1"` gives the
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* literal words `"my` and `dir"/x`, then `--since` and `HEAD~1`, so a quoted
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* value never swallows a later flag. Nothing is expanded: the function only
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* slices the string.
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*
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* @param {string} text
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* @returns {Array<{ value: string, start: number, end: number }>}
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@ -156,8 +163,8 @@ export function tokenize(text) {
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const q = text[i];
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if (q === '"' || q === "'") {
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let j = text.indexOf(q, i + 1);
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while (j !== -1 && j + 1 < n && !isSpace(text[j + 1])) j = text.indexOf(q, j + 1);
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if (j !== -1) {
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while (j !== -1 && !isSpace(text[j - 1]) && j + 1 < n && !isSpace(text[j + 1])) j = text.indexOf(q, j + 1);
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if (j !== -1 && !isSpace(text[j - 1])) {
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out.push({ value: text.slice(i + 1, j), start, end: j + 1 });
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i = j + 1;
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continue;
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